Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>
Suppose an infinity sequence defined by:
Then we have to calculate the following limit:
If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:
Hence the limit is:
Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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Answer:
The correct option is A) 3 square inches; .
Step-by-step explanation:
It is given that the length of the frame is (2x-3) and the width is (x-2)
The area of the rectangle is:
Where, A is the area l is the length and w is the width of the rectangle.
Put and in the area of the rectangle.
The area of the frame expressed as a polynomial is .
Now substitute x=3 in .
The area of the frame is 3 square inches.
Hence, the correct option is A) 3 square inches; .
Answer:
-123
Step-by-step explanation:
The remainder theorem says that when a polynomial is divided by a linear factor x - c (note the minus sign), the remainder is the value of the polynomial at x = c.
When a polynomial P(x) is divided by x - c, the remainder is P(c). In other words, to find the remainder, plug in c for x.
You're dividing by x + 4 which is the same thing as x - (-4) -- the role of c is being played by -4.
3(–4)^3 – (–4)^2 – 20(–4) + 5 = –123
I think it's a rational number.