Answer:
A) The model exists: f(x) = -3x^2 +4x -4
Step-by-step explanation:
A quadratic model will always exist for 3 given points, provided they are not on a line. In that case, a linear model is appropriate.
Here, the slope between -1 and 0 is positive, and the slope between 0 and 3 is negative. Thus, we know these points are not collinear, and a model must exist.
The model is most easily found using a quadratic regression tool. Such is shown in the attachment. It tells us that ...
f(x) = -3x^2 +4x -4
Answer:
x-axis is for the independent variable
Step-by-step explanation:
Answer:
the answer is :)
Step-by-step explanation:
The answer it should be: 28,000
X is left and right
hmm
see the aproximate slope
see endpoints
ok, so from about (0,3) to (35,30)
slpoe is 27/35
so
y=(27/35)x+3 about
so when x=
ok, so according to the garph, when x=35, y=30, not 20
ok, so when x=40
y=(27/35)x+3
y=(27/35)*40+3
y=33.8571 about for x=40