22.5 mL of an HNO3 solution were titrated with 31.27 mL of a .167 M NaOH solution to reach the equivalence point. What is the mo larity of the HNO3 solution
1 answer:
Answer:
M₂ = 0.23 M
Explanation:
Given data:
Volume of HNO₃ = 22.5 mL
Volume of NaOH = 31.27 mL
Molarity of NaOH = 0.167 M
Molarity of HNO₃ = ?
Solution:
M₁ = Molarity of NaOH
V₁ = Volume of NaOH
M₂ = Molarity of HNO₃
V₂ = Volume of HNO₃
M₁V₁ = M₂V₂
0.167 M × 31.27 mL = M₂ × 22.5 mL
5.2 M. mL = M₂ × 22.5 mL
M₂ = 5.2 M. mL /22.5 mL
M₂ = 0.23 M
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