What is the volume of the regular pyramid below?
2 answers:
The picture in the attached figure
we know that
volume of the regular pyramid=(1/3)*area of the base*height
area of the base=12*12-----> 144 units²
height=71 units
substitute
volume of the regular pyramid=(1/3)*144*71-----> 3408 units³
the answer is
3408 units³
we know that
volume of the regular pyramid=(1/3)*area of the base*height
area of the base=12*12-----> 144 units²
height=71 units
substitute
volume of the regular pyramid=(1/3)*144*71-----> 3408 units³
the answer is
3408 units³
Answer:
Option d.
Step-by-step explanation:
Consider the below figure attached with this question.
From the given figure it is clear that the measure side of base is 12 units and height is 71 units.
The base of the pyramid is a square. So the area of base is
The volume of a regular pyramid is
where, B is area of base and h is height of the pyramid.
Substitute B=144 and h=71 in the above formula.
The volume of regular pyramid is 3408 cubic units.
Therefore, the correct option is d.
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Answer:
46
Step-by-step explanation:
Let represent a number with
in the ten's position and
is the one's position.
This means actually has value of
.
We are given the sum of those digits of is 10; this means
.
It says if 18 is added to the number , then the result is
.
So has value
and
has value
.
We are given then:
Subtract on both sides:
Simplify:
Subtract on both sides:
Divide both sides by 9:
Rearrange by commutative property:
So the system of equations we want to solve is:
-------------------------Add equations together (this will eliminate the variable and allow you to go ahead and solve for
:
Divide both sides by 2:
Simplify:
If and
, then
.
since 4+6=10.
So the original number is (46).
18 more than 46 is 18+46=(64) which is what we wanted.
We also have the sum of 4 and 6 is 10 as well.