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2 years ago

HELP PLEASE PLEASE!!!!!

Mathematics

1 answer:

Firlakuza [10]2 years ago

7 0

The answer is the first choice because it is on google.

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Claire is 2 year younger than her sister. The

natta225 [31]

Given:

Claire is 2 year younger than her sister.

The sum of ages is no less than 44 years.

To find:

Inequality and find the youngest age Claire can be.

Solution:

Let the age of Claire be x.

Her sister's age = x+2

Sum of their ages is no less than 44 years. It means the sum ages is greater than or equal to 44.

$x+(x+2)\geq 44$

$2x+2\geq 44$

$2x\geq 44-2$

$2x\geq 42$

Divide both sides by 2.

$x\geq 21$

It means, Claire age can be greater than or equal to 21. So, the youngest age Claire can be 21 years old.

Therefore, the required inequality is $2x+2\geq 44$ and the correct option is B.

4 0

2 years ago

Find the volume of the cone.

Andrew [12]

Answer:

V= 628.32

Step-by-step explanation:

4 0

3 years ago

If one endpoint is (-6,4) and the midpoint is (4,8) what would be the other endpoint ???? if you can explain it would be great

krek1111 [17]

I believe the next one would be 13.2 because if you add 8.4 to -6.4 it gets 4.8 so you just do the same thing

8 0

2 years ago

How many times greater os 46 than 0.46?

Usimov [2.4K]

10,000 times greater.

7 0

2 years ago

Read 2 more answers

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

6 0

2 years ago