Find the area of the rhombus. d1 = 14 m; d2 = 18 m The area of the rhombus is ? m2.

Mathematics

2 answers:

xxTIMURxx [149]2 years ago

8 0

Answer:

Area of rhombus = 126 m²

Explanation:

We are given that the two diagonals of the rhombus are:

D₁ = 14 meters and D₂ = 18 meters

The area of the rhombus using its diagonals can be calculated using the following rule:

$Area = \frac{D_1 * D_2}{2}$

Substitute with the given values to get the area as follows:

$Area = \frac{14*18}{2}=126 m^2$

Hope this helps :)

Maksim231197 [3]2 years ago

3 0

Answer:

2.16m2

Step-by-step explanation:

You might be interested in

Algebra help - asymptotes

motikmotik

Find where the equation is undefined ( when the denominator is equal to 0.

Since they say x = 5, replace x in the equation see which ones equal o:

5-5 = 0

So we know the denominator has to be (x-5), this now narrows it down to the first two answers.

To find the horizontal asymptote, we need to look at an equation for a rational function: R(x) = ax^n / bx^m, where n is the degree of the numerator and m is the degree of the denominator.

In the equations given neither the numerator or denominators have an exponent ( neither are raised to a power)

so the degrees would be equal.

Since they are equal the horizontal asymptote is the y-intercept, which is given as -2.

This makes the first choice the correct answer.

8 0

2 years ago

What is the distance between (4,7) and (2,2)?

algol [13]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 4}}\quad ,&{{ 7}})\quad 
% (c,d)
&({{ 2}}\quad ,&{{ 2}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{(2-4)^2+(2-7)^2}\implies d=\sqrt{(-2)^2+(-5)^2}
\\\\\\
d=\sqrt{4+25}\implies d=\sqrt{29}$