Question

What volume in liters of 5.75×10−2 M KH2AsO4 contains 6.30 g KH2AsO4?

Answer 1

Answer : The volume of solution is, 0.609 L

Explanation : Given,

Mass of $KH_2AsO_4$ = 6.30 g

Molar mass of $KH_2AsO_4$ = 180 g/mole

Concentration = $5.75\times 10^{-2}M$

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

$\text{Molarity}=\frac{\text{Mass of }KH_2AsO_4}{\text{Molar mass of }KH_2AsO_4\times \text{Volume of solution (in L)}}$

Now put all the given values in this formula, we get:

$5.75\times 10^{-2}M=\frac{6.30g}{180g/mole\times \text{Volume of solution (in L)}}$

$\text{Volume of solution (in L)}=0.609L$

Therefore, the volume of solution is, 0.609 L