Answer:
Graph the trigonometric function using the amplitude, period, phase shift, and vertical shift.
Amplitude: 1
Period: π
Phase Shift: 0 (
0 to the right)
Vertical Shift: 1
For a), wouldn't you multiply the cost of a twin by the quantity of a twin beige (N) and the cost of a queen by the quantity of the queen beige (N) and then the cost of the king by the quantity of the king beige (N) for CN and do the same thing but with the south quantities?
And then for b), it's just comparing which one had the most money and find the difference...
And then C), would be relatively self explanatory where CN would be the potential profit in N and CS would be the potential profit in S and then CN+CS would be the potential profit total?
Answer:
<h2>(+)(-)√30</h2><h2>#option c</h2>
Step-by-step explanation:
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<h3>
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When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
Learn more about algebra:
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D. it represents the product of two rational numbers and is equivalent to an irrational number
