Answer:
0.25
Step-by-step explanation:
We have a total of ten student, and three students are randomly selected (without replacement) to participate in a survey. So, the total number of subsets of size 3 is given by 10C3=120.
On the other hand A=Exactly 1 of the three selected is a freshman. We have that three students are freshman in the classroom, we can form 3C1 different subsets of size 1 with the three freshman; besides B=Exactly 2 of the three selected are juniors, and five are juniors in the classroom. We can form 5C2 different subsets of size 2 with the five juniors. By the multiplication rule the number of different subsets of size 3 with exactly 1 freshman and 2 juniors is given by
(3C1)(5C2)=(3)(10)=30 and
Pr(A∩B)=30/120=0.25
Answer:
y=7/10+3/10
Step-by-step explanation:
Answer:
35x = 155-15
It will take 4 months.
Step-by-step explanation:
The answer is 13 you have to add the top and bottom
Answer:
Step-by-step explanation:
-5 + (8 x -7)
using PEMDAS, (8 x -7) = -56
so -5 + -56 = -61