Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
I think its better than other types of math.
Step-by-step explanation:
As an improper fraction, it is
.
Answer:
Can't really show a graph but I'll explain how to:
Step-by-step explanation:
Plot the point (0,-2) since -2 is the y=intercept. After, just count-down 1 unit and count 5 units to the right. I hoped this helped!
Answer:
a = 86y
Step-by-step explanation:
Given:
Number of applicants per year = 86
Find:
Equation represent total applicants
Computation:
Assume;
Total number of years = y
Total number of applicants = a
So,
Total number of applicants = Number of applicants per year x Total number of years
a = 86 x y
a = 86y