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2 years ago

AB and BC are tangent to circle D. Find x if AB = 2x + 9 and BC = 3x + 6. Find x.

2 answers:

6 0

It woulds be x+15 because if you take 2x and subtracted from the 3x then you get x and then you add the 9 and 6 witch you get 15

sergij07 [2.7K]2 years ago

4 0

Answer:

the value of X comes out to be equal to 3

Step-by-step explanation:

since AB and BC are tangent to the circle D

then the length of the tangent will be same

AB will be equal to BC

where,

AB = 2 x + 9

and

BC = 3 x + 6

2 x + 9 = 3 x + 6

3 x - 2 x = 9 - 6

x = 3

hence, the value of X comes out to be equal to 3

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Answer:

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Step-by-step explanation:

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2 years ago

What is the slope intercept from two points <br><br> (1,4)and(2,2)<br><br> Y=______

vodomira [7]

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2 years ago

Read 2 more answers

Pleasee help ASAP!! No links pleaseee!!!

Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(2-0)^2+(4-1)^2}$

$AB=\sqrt{(2)^2+(3)^2}$

$AB=\sqrt{4+9}$

$AB=\sqrt{13}$

Similarly,

$BC=\sqrt{(6-2)^2+(0-4)^2}$

$BC=\sqrt{(4)^2+(-4)^2}$

$BC=\sqrt{16+16}$

$BC=\sqrt{32}$

$BC=4\sqrt{2}$

Now, the length of the rectangle is $AB=\sqrt{13}$ and the width of the rectangle is $BC=4\sqrt{2}$ . So, the area of the rectangle is:

$A=length \times width$

$A=\sqrt{13}\times 4\sqrt{2}$

$A=4\sqrt{26}$

$A\approx 20$

Therefore, the area of the rectangle is 20 square units.

3 0

2 years ago

Can someone solve -2(+3 + -4 + -8 + +7)? I forgot how to do integers :/

aleksandrvk [35]

Answer:

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2 years ago

Can you solve this??

gavmur [86]

Answer:

The answer is c

Step-by-step explanation:

The middle problem is adding, the others are taking away, so C is the correct answer

3 0

1 year ago