If they're both equal $20 but there is many different ways to answer this like 19 plus 21
You divide 71 by 9 to get 7 8/9
Answer:
Let p(x) = x3 + ax2 + bx +6
(x-2) is a factor of the polynomial x3 + ax2 + b x +6
p(2) = 0
p(2) = 23 + a.22 + b.2 +6 =8+4a+2b+6 =14+ 4a+ 2b = 0
7 +2 a +b = 0
b = - 7 -2a -(i)
x3 + ax2 + bx +6 when divided by (x-3) leaves remainder 3.
p(3) = 3
p(3) = 33 + a.32 + b.3 +6= 27+9a +3b +6 =33+9a+3b = 3
11+3a +b =1 => 3a+b =-10 => b= -10-3a -(ii)
Equating the value of b from (ii) and (i) , we have
(- 7 -2a) = (-10 - 3a)
a = -3
Substituting a = -3 in (i), we get
b = - 7 -2(-3) = -7 + 6 = -1
Thus the values of a and b are -3 and -1 respectively.
Step-by-step explanation:
Answer:
Step-by-step explanation:
y = 3x - 5
y = 1/3x + 3
3x - 5 = 1/3x + 3....multiply everything by 3 to get rid of the fraction
9x - 15 = x + 9
9x - x = 9 + 15
8x = 24
x = 24/8
x = 3
y = 3x - 5
y = 3(3) - 5
y = 9 - 5
y = 4
solution is : x = 3 and y = 4...or (3,4) <==
