Answer:
3a:20d+35
3b:35u+49q+56
4a:15+20t
4b:96k+120t+84
5a:24t+108m+60
5b:56q+28b+35
6a:14q+10w+24
6b:54v+99+27t
7a:16g+24+24c
7b:30a+55+50d
(i think thats what they are but the picture is small so its kind of hard to see)
Step-by-step explanation:
(since theres 10 total ill just give an example on how i solved 5a)
5(4d+7)
simplify into: (5•4d)+(5•7)
multiply: (20d)+(35)
since you do not know what d is, you cannot add them
remove parentheses once done:20d+35
(you don't need parentheses since multiplication come before addition but its easier to just use them)
<h2>Hope this helps</h2>
Answer:
no
Step-by-step explanation:
.....................
Idk what are the possible answers
X. 1. 2. 3. 4. 5. 6 are all the possible events when rolling a die. If it is a fair die then the probability of rolling any number is 1/6. So the probability of rolling at most a two is p(1)+ p(2)= 2/6 or 1/3
-10 -9 -8 -6 -5 -4 -3 -2 -1 0 1 2 3 4
Go back -5 places and you will land on the answer of -8
Hope this helps! :)
