What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]
Answer:
The Interquartile range is 10.
Step-by-step explanation:
First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.
So, 23-13=10
The Answer will be 10, the interquartile range is 10.
Hope this helps!
sin = 3/7
1 = sin²0 + cos²0
cos²0 = 1 - 9/49
cos²0 = 40/49
cos0 = √(40) / 7
since its in Quadrant 2 the sin is positive and cos is negative
cos0 = - √(40) / 7
Answer:
9
Step-by-step explanation:
1, 3, 5, 9, 15, 19, 19
Answer:
Step-by-step explanation:
step 1
Find the radius of the circle
we know that
The distance between the center and any point that lie on the circle is equal to the radius
we have the points
(5,-4) and (-3,2)
the formula to calculate the distance between two points is equal to
substitute the values
step 2
Find the equation of the circle
we know that
The equation of a circle in standard form is equal to
where
(h,k) is the center
r is the radius
we have
substitute
-50m^4 n^7 = 10m^2n^7(-5m^2)<span>
and
40m^2 n^10 = 10</span>m^2 n^7(4n^3)
Answer: GCF = 10m^2 n^7