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3 years ago

Find the area of the shaded region.

Mathematics

1 answer:

Papessa [141]3 years ago

8 0

Answer:

21.46 cm²

Step-by-step explanation:

because the question want only for the SHADED REGION but NOT AREA OF THE SQUARE

(if we just multiply 10x10. you will get the area of a square which is hundered)

To find the shaded region:

1. area of a circle is πr² (we have 4 circle there)

2. Find the area of all circle

# how do we know the radius?

- half of 10 is 5

- 5 is the diameter of each circle

- the radius is half of 5 which is 2.5

- π(2.5)² = 25/4π (area of 1 circle)

3. since we have 4 circle then, 25/4π x 4 = 25π

4. the area of the square is 100cm²

5. we want the shaded region so we have to minus the area of the circle

6. 100 - 25π (use your calculator to find the answer)

answer should be 21.46 cm²

(hope this helps)

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Identify the slope of the line for the equation y = 10x + 3.

Mrrafil [7]

Answer:

D) 10

Step-by-step explanation:

The slope of the line y=10x+3 is 10 because in the slope form y=mxtb m represents the slope. In this case 10 is m, therefore the slope is 10. This mean the slope rises 10 units and runs 1 unit since slope is also known as rise/run.

8 0

2 years ago

100 POINTS!!! ALGEBRA 1 PLEASE HELP!!! BRAINLIEST IF CORRECT

Ainat [17]

Answer:

<h2>1. (-6, 0) and (-1, 0)</h2><h2>2. not exist</h2><h2>3. (5, 0)</h2>

Step-by-step explanation:

The zeros of a quadratic function are x-intercepts of parabola.

Graph #1:

x = -6 and x = -1

Graph #2:

not exist

Graph #3:

x = 5

5 0

2 years ago

Read 2 more answers

Professor Halen teaches a College Mathematics class. The scores on the midterm exam are normally distributed with a mean of 72.3

lbvjy [14]

Answer:

14.63% probability that a student scores between 82 and 90

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 72.3, \sigma = 8.9$

What is the probability that a student scores between 82 and 90?

This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So

X = 90

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{90 - 73.9}{8.9}$

$Z = 1.81$

$Z = 1.81$ has a pvalue of 0.9649

X = 82

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{82 - 73.9}{8.9}$

$Z = 0.91$

$Z = 0.91$ has a pvalue of 0.8186

0.9649 - 0.8186 = 0.1463

14.63% probability that a student scores between 82 and 90

3 0

2 years ago

2. 2(x+1.25) = 3.5

dangina [55]

Answer:

x = 0.5

Step-by-step explanation:

Given

2(x + 1.25) = 3.5 ← divide both sides by 2

x + 1.25 = 1.75 ( subtract 1.25 from both sides )

x = 0.5

8 0

2 years ago

Read 2 more answers

Suppose that there are 15 antennas in a store, of which 3 are defective. Assume all the defectives and all the functional antenn

ohaa [14]

Answer:

Step-by-step explanation:

Total number of antenna is 15

Defective antenna is 3

The functional antenna is 15-3=12.

Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.

So,

We line up the 13 good ones, and see where the bad one will fits in

__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __

Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.

Then,

There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement

ⁿCr= n!/(n-r)!r!

The number of arrangement is

14C3=14!/(14-3)!3!

14C3=14×13×12×11!/11!×3×2

14C3=14×13×12/6

14C3=364ways

7 0

2 years ago