Answer:
The height of the Empire State Building is 0.1944miles (1026.43ft)
Step-by-step explanation:
This question can be answered using <u>Trigonometry</u>, and we can draw a sketch from the information provided. There is one attached.
From the problem's statement, we know that the <em>angle of elevation to the top of the building from the ground</em> is α=11°, and there is <em>a distance of </em><em>1mi</em><em> from the base of the building</em>.
As we can see from the sketch, the given information permits us to draw a right-angled triangle and we can find the <em>height H</em> using trigonometric functions.
We need to remember that in a right-angled triangle, <em>tangent function</em> is defined as , that is, the <em>ratio</em> of the <em>opposite side</em> to the angle in question (in this case α) to the <em>adjacent side</em> to this angle.
The opposite side of angle α is H, and the adjacent side is the distance given, that is, 1 mile.
Looking at the sketch attached, we can see that , and that , so the height of the Empire State Building, according to this information, is H = 0.1944mi.
The value of the tangent of the angle α was rounded to tan(11°)=0.1944.
A value of tan(11°)=0.19438030913771848424...could be found in WolframAlpha's website.
To find the equivalent distance in <em>feet</em>, we know that there are 5280ft in a mile, so, using <em>proportions</em>:
⇒
, which results in 1026.43ft.
This problem could be solved also using the <em>Law of Sines</em>, but using more steps, and knowing that the sum of the internal angles of a rigth-angled triangle equals 180°.