Answer:
<u>, where "n" is number of objects per page.</u>
Step-by-step explanation:
<em>The amount of objects each page could hold is given by dividing the amount of objects that you have, by the number of pages. </em>
<em>• Let the number of objects per page be "n".</em>
<em>Then, the equation that gives us the number of objects for each page, in such way that we have an equal amount of objects per page is:</em>
.
Answer:
AGREE!
Step-by-step explanation:
"I agree with Lin, she used the correct formula to get this answer"
Answer:
cubes are 3-d while squares are 2-d so in order to solve them you need different equations.
In 1, t<span>here are 6 outcomes for each die, so for three dice, the total combination is 6 x 6 x 6 = 216 outcomes. Hence, t</span><span>he probability of any individual outcome is 1/216 </span>
The outcomes that will add up to 6 are
<span>1+1+4 </span>
<span>1+4+1 </span>
<span>4+1+1 </span>
<span>1+2+3 </span>
<span>1+3+2 </span>
<span>2+1+3 </span>
<span>2+3+1 </span>
<span>3+1+2 </span>
<span>3+2+1 </span>
<span>2+2+2 </span>
<span>Hence the probability is </span><span>10/216 </span>
In 3, the minimum sum of the three dice is 3. so we start with this
<span>P(n = 3) </span>
<span>1+1+1 ; </span><span>1/216 </span>
<span>P(n = 4) </span>
<span>1+1+2 </span>
<span>1+2+1 </span>
<span>2+1+1 ; </span><span>3/216 </span>
<span>P(n = 5) </span>
<span>1+1+3 </span>
<span>1+3+1 </span>
<span>3+1+1 </span>
<span>1+2+2 </span>
<span>2+1+2 </span>
<span>2+2+1; </span><span>6/216
The sum in 3 is 10/216 or 5/108</span>
The answer is
Each roll has a 0.333 probability of being composite.
<em>(I just took the test,
B was the answer)</em>
