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2 years ago

Identify the equation in slope-intercept form for the line containing the point (−3,5) and parallel to y=−2/3x+53.

Mathematics

1 answer:

Alexeev081 [22]2 years ago

3 0

Answer:

y=−2/3x+3

Step-by-step explanation:

I graphed the point and the equation given below. I used the same slope in the new equation as the original equation. The y-intercept is 3 because the line goes through (0,3).

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D. No balance transfer fee

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2 years ago

Read 2 more answers

Mr.price flew 4,908 from New York then he flew 3525 miles from Hawaii to Texas how much farther was mr.price trip from New York

alexandr1967 [171]

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2 years ago

Sandy mixed together 9 gallons of one brand of juice and 8 gallons of a second brand of juice, which contains 48 percent real fr

Gekata [30.6K]

Answer:

14 % pure juice comes from first brand

Step-by-step explanation:

Mixture:

17 gal 30% contains: 17x 30% = 5.10 gal pure juice

Second brand:

8 gal 48% contains: 8x40% = 3.84 gal pure juice

5.10 − 3.84 = 1.26 gal

1.26 gal is coming from 9 gal of first brand

The percentage of first brand is:

(1.26/9) x100 = 14 % pure juice.

8 0

2 years ago

Explain howyou wouldestimateto subtract 189 from 643

kupik [55]

I would estimate 643 - 189 by rounding 643 to the tens place and 189 to the hundreds place.

643 => 640

189 => 200

Now you can subtract 200 from 640.

640 - 200 = 440

6 0

3 years ago

Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa

zimovet [89]

Answer:

$x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

Step-by-step explanation:

We are given that a quadratic equation

$x^2-x-1=0$

We have to solve the equation by completing square and find the value of b.

$(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0$

$(x-\frac{1}{2})^2-\frac{1}{4}-1=0$

$(x-\frac{1}{2})^2-\frac{1-4}{4}=0$

$(x-\frac{1}{2})-\frac{5}{4}=0$

$(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0$

$(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2$

$x-\frac{1}{2}=\frac{\sqrt5}{2}$ and $x-\frac{1}{2}=-\frac{\sqrt5}{2}$

$x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}$

And $x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}$

Therefore, $x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

6 0

2 years ago