<span>So we want to know how much clay did Joseph add after he built the cone. So the formula for the volume of the cone is V=(1/3)*pi*r^2*h where r is the radius and h is height. We know h1=12cm and r1=6cm, r2=6cm and h2=18 cm. So to get the amount of added clay Va we simply subtract the volume of the clay of the first cone V1 from the volume of the second cone V2: Vd=V2-V1=(1/3)*pi*(r1^2)*h1 - (1/3)+pi*(r2^2)*h2. Va=678.24 cm^3-452.39 cm^3= 266.08 cm^3.</span>
I think it is -37m+17 but I am not sure
Your question is calling the figure ABCD, but the image is showing PQRS
Using the letters that you wrote:
Because the figure was only rotated and not scaled , the sides with the same letters would still be the same
So AB would be the same as A'B' ( Length of AB = Length of A′B)
and
BC = B'C'
CD = C'D'
AD = A'D'
Or by the picture:
PQ = P'Q'
QR = Q'R'
RS = R'S'
PS = P'S'
Answer:
7 x 2, 14, the area, then use pie, 3.14 to get the circle
Step-by-step explanation:
Answer:
y6%cf4yergby65thrbgtrvbh
Step-by-step explanation:
