5 horses with a combined weight of 6,240 pounds
horse trailer has a limit of 8,000 pounds of horse and tacks.
Find the weight of tack, t, for each horse that Cari can allow.
5t + 6,240 < 8,000
5t + 6,240 < 8,000
- 6,240 -6,240
5t < 1,760
<span>÷5 ÷5 </span>
t < 352
Each horse can carry a tack that weighs no more than 352 pounds.
Any tack that weighs beyond <span>352 </span>pounds is will exceed the maximum carrying capacity of the horse trailer.
Answer:
8x^2 - 2xy + 3y^2
Step-by-step explanation:
Use the FOIL method
8x^2 + 4xy - 6xy + 3y^2
8x^2 - 2xy + 3y^2
Answer:
d=0
Step-by-step explanation:
Because multiplication is commutative, we can rearrange the expression however we want. So, let's put the constant expressions together, and the variable expressions together:
(3 x 4) x (d^-4 x d^4)
The first term is easy enough: (3 x 4) = 12
For the second term, when exponent terms have the same "base" (in this case, d), the exponents can be added together. So, the second term yields d^(-4 + 4) = d^0. Any number raised to the zero power equals 1, EXCEPT for the sole number of zero. 0^0 is undefined, but any other number raised to the zero power equals 1.
So, if d equals any number other than zero, the expression becomes
(12) x (1) = 12
The best way to express the answer would be that the expression equals 12 except that it is undefined if d=0