or
Answer:
Solution given:
y=2x²-5x+6.....[1]
y=3x+3.........….[2]
solving equation 1&2
2x²-5x+6=3x+3
2x²-5x-3x+6-3=0
2x²-8x+3=0
comparing above equation with ax²+bx+c=0 we get
a=2
b=-8
c=3
by using quadratic equation
taking positive
taking negative
Solve for r.
You want to get r by itself on one side on the equal sign.
bh + hr = 25
Subtract bh from both sides.
hr = 25 - bh
Divide h on both sides.
r = 25 - bh / h
The two h's cancel each other out.
r = 25 - b
Hope this helps!