I think that you should imagine what regular shape the figure would have been.
The fact that two sides are 9inches makes me think it would have been a square.
The area of a square is A= l² where l is the length of one side and A=area
A=9*9
A=81 in.²
Next, find the area of the part that is taken away,(it looks like a triangle). to find that, if the figure was a square, the length on top would be 9 not 5, so the length gone is 9-5=4, so the base of the triangle is 4,
If the figure was a square, the length on the other side would be 9 not 4 so the length gone is 9-4=5, so the height of the triangle is 5
the area of a triangle is A= 1/2bh, where A is area, b is base and h is height.
A=1/2*4*5 A=10 so the area of the part gone is 10 inches²
The area of the figure is the area of the square -the area of the triangle
A=81-10
A=71inches²
,
Se necesitan los puntos que representen a Y1 y X1, si no no te puedo ayudar solo te puedo dar la formula
La formula para la ecuación es:
(Y-Y1)=m (X-X1)
Answer: β ≠ ±1
Step-by-step explanation: For a system of equations to have an unique solution, its determinant must be different from 0: det |A| ≠ 0. So,
det ≠ 0
Determinant of a 3x3 matrix is calculated by:
det
β ≠ ±1
For the system to have only one solution, β ≠ 1 or β ≠ -1.
The answer is A. If there are 3 thirds (1/3s) per yard and there are 6 yards, 3*6=18. Because the last cut will make two 1/3-yard segments, the answer is 17 cuts and not 18.
60,000 and 6,000 one is just 10 times bigger