The surface area increases by a factor of 4. 2^2= 4.
The area of the long side is 3×1= 3cm^2 on the small prism.
The area of the long side is 6×2= 12cm^2 on the large prism.
12/3= 4.
Answer:
Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m × (as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
=
P(success) = 0.4 P(failure) = 0.6
8C2 (0.4)² * (0.6)^6
P(2 success) =0.290
Answer: Yes. (gof)(0) = -5
(gof)(0) means you will find the function of g(f(0)), which means we will find f(0) and plug that value in for x in the function g(x)
We know f(0) is -1, so we can plug -1 into the equation of g(x)
(gof)(0) = (-1) - 4
(gof)(0) = -5
Answer:
number 3
Step-by-step explanation:
thats my calcue