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2 years ago

Someone one PLEASE HELP I've been stuck for like 2 hours

Mathematics

2 answers:

Dmitry_Shevchenko [17]2 years ago

7 0

72÷4= 18 the right answers and then was 25 questions minus the 18 right answers 7 was the wrong answers, so i think 25-18= 7, thats what i think, is little tricky i hope is right

Mnenie [13.5K]2 years ago

6 0

I agree with Darkcjshadow, they explained it perfectly, good luck on your quiz :'D

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Savatey [412]

I don’t think so it’s right question

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2 years ago

The Answer to This Question

xenn [34]

Recall the Trigonometric Ratio below:

$\tt{ \large{sin \theta = \frac{opposite}{hypotenuse} } }\\ \tt{\large{cos \theta = \frac{adjacent}{hypotenuse} }} \\ \tt{ \large{tan \theta = \frac{opposite}{adjacent} }}$

For csc, sec and cot - they are reciprocal of sin,cos and tan.

$\tt{ \large{csc \theta = \frac{1}{sin \theta} } }\\ \tt{ \large{sec \theta = \frac{1}{cos \theta} }} \\ \tt{ \large{cot \theta = \frac{1}{tan \theta} }}$

What we know now is our hypotenuse, adjacent and opposite length.

hypotenuse = 15
opposite = 12
adjacent = 9

Therefore,

$\large{sin \theta = \frac{12}{15} \longrightarrow \frac{4}{5} } \\ \large{cos \theta = \frac{9}{15} \longrightarrow \frac{3}{5} } \\ \large{ tan \theta = \frac{12}{9} \longrightarrow \frac{4}{3} }$ As for the reciprocal of three trigonometric ratio. We just swap the numerator and denominator.

$\large{csc \theta = \frac{15}{12} \longrightarrow \frac{5}{4} } \\ \large{sec \theta = \frac{15}{9} \longrightarrow \frac{5}{3} } \\ \large{cot \theta = \frac{9}{12} \longrightarrow \frac{3}{4} }$

Answer

sin = 12/15 —> 4/5
cos = 9/15 —> 3/5
tan = 12/9 —> 4/3
csc = 15/12 —> 5/4
sec = 15/9 —> 5/3
cot = 9/12 —> 3/4

The first is non-simplifed form while the second that has the arrow pointing is the simplest form.

Let me know if you have any doubts.

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