Answer:
Initial concentration of HI is 5 mol/L.
The concentration of HI after is 0.00345 mol/L.
Explanation:
Rate Law:
Rate constant of the reaction = k =
Order of the reaction = 2
Initial rate of reaction =
Initial concentration of HI =
Final concentration of HI after t = [A]
t =
Integrated rate law for second order kinetics is given by:
The concentration of HI after is 0.00345 mol/L.
Answer:
2.05moles
Explanation:
The balanced chemical equation in this question is as follows;
Sn + 2H2SO4 → SnSO4 + SO2 + 2H2O
Based on the above equation, 2 moles of H2SO4 reacted to produce 1 mole of SnSO4
However, the mass of SnSO4 produced is 219.65 grams. Using mole = mass/molar mass, we can find the number of moles of SnSO4 produced.
Molar mass of SnSO4 where Sn = 118.7, S = 32, O = 16
= 118.7 + 32 + 16(4)
= 150.7 + 64
= 214.7g/mol
mole = 219.65/214.7
mole = 1.023mol
Therefore, if 2 moles of H2SO4 reacted to produce 1 mole of SnSO4
1.023 mol of SnSO4 produced will cause: 1.023 × 2/1
= 2.046moles of H2SO4 to react.
Answer:
The pH does not decrease drastically because the NaOH reacts with the <u>D) Benzoic acid</u> present in the buffer solution.
Explanation:
The hydroxide ions will react with acidic part of the solutions, it means the benzoic acid, so it will form the conjugate base, the benzoate ion.
Answer:
6.3 atm
Explanation:
P2=T2P1/T1
Change C to K
We can check this by knowing that P and T at constant V have a proportional relationship; Hence, this is correct.
Scientists observe the world around them, from which to draw questions. Their predictions as to the answer are what we call a “hypothesis”. Thus, a scientist’s job is to answer the very hypotheses that they and their piers come up with.