<h2><u>
Answer with explanation</u>
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Let 
be the population mean.
As per given , we have
Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.
Also, population standard deviation is given 
, so we perform one-tailed z-test.
Test statistic : 
, where = Population mean
= Population standard deviation
n= sample size
= Sample mean
For n= 18 , 
, , 
, we have
P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12) [∵ P(Z>z)=1-P(Z≤z)]\
=1- 0.0340=0.9660
Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.
[We reject null hypothesis if p-value is larger than the significance level . ]
Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .
AFB, the sides are similar
You forgot to put the options and the rest of the equation
Answer:
300ml
Step-by-step explanation:
As values are missing in your question, the complete question is:
In the lab, Leila has two solutions that contain alcohol and is mixing them with each other. Solution A is 6% alcohol and Solution B is 20% alcohol. She uses 400 milliliters of Solution A. How many milliliters of Solution B does she use, if the resulting mixture is a 12% alcohol solution?
Considering x=ml of 20% solution B
Therefore, 400+x=ml of resulting 12% solution
Solution A alcohol+ solution B alcohol= Alcohol solution
6% (400)+ 20%x = 12%(400+x) ->(converting percentage into decimal)
.06*400+.2x=.12(400+x)
24+.2x=48+.12x
.08x=24
x=24/.08=300 ml
she used 300 milliliters of 20%Solution B in resulting mixture.
Answer:
6,9 hope this is it
Step-by-step explanation:
