Let the first number be 'x' and the second number is 'y'
Equation 1: x + y = 52
Equation 2: x - y = 38
Rearranging equation 2 to make either x or y the subject
x = 38 + y
Substituting x = 38 + y into equation 1
x + y = 52
(38+y) + y = 52
38 + 2y = 52
2y = 52 - 38
2y = 14
y = 7
Substitute y = 7 into either equation 1 or equation 2 to find x
x + y = 52
x + 7 = 52
x = 52 - 7
x = 45
x = 45
y = 7
Answer:
The values in the table, taking into account the quadratic equation, are:
- x -3 -2 -1 0 1 2 3 4
- y <u>16</u> 9 <u>4</u> 1 <u>0</u> 1 <u>4</u> 9
Step-by-step explanation:
To obtain the values of the table, you must use the quadratic equation given:
Now, you must replace the x with the one that is above the value you want to find, in the first case, we're gonna replace the value x with -3:
- y = x^2 - 2x + 1
- y = (-3)^2 - 2*(-3) + 1
- y = 9 + 6 + 1
- <u>y = 16</u>
When x is -1
- y = x^2 - 2x + 1
- y = (-1)^2 - 2*(-1) + 1
- y = 1 + 2 + 1
- <u>y = 4</u>
When x is 1
- y = x^2 - 2x + 1
- y = (1)^2 - 2*(1) + 1
- y = 1 - 2 + 1
- <u>y = 0</u>
When x is 3:
- y = x^2 - 2x + 1
- y = (3)^2 - 2*(3) + 1
- y = 9 - 6 + 1
- <u>y = 4</u>
At last, the graph must be as the attached picture I give you, but <u><em>remember in y-axis you must use 1 cm as unit and in the x-axis you must use 2 cm as unit, in this form, the graph will not be so elongated as the picture I attach, It would be wider</em></u>.
Answer:
19.488
Step-by-step explanation:
8.12 x 2.4 = 19.488