I think the answer is D but i could be wrong
Answer:
1.748 mM
Explanation:
Concentration in g / L = Molarity × molar mass
molar mass of calcium carbonate = 100.0869 g/mol
175 mg/L = 175 ÷ 1000 = 0.175 g/L
0.175 g/L = Molarity × 100.0869 g/mol
(0.175 g/L) / 100.0869 = Molarity
Molarity = 0.001748 M
CaCO₃ → Ca²⁺ + CO₃²⁻ when it dissociate in water.
1 M of CaCO₃ yielded 1 M of Ca²⁺
0.001748 M of CaCO₃ will also yield 0.001748 M of Ca²⁺
then 0.001748 × 1000 = 1.748 mM concentration of Ca²⁺
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