Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
Answer:B
Step-by-step explanation:
y=13xy=\dfrac{1}{3}xy=31xy, equals, start fraction, 1, divided by, 3, end fraction, x
Answer:
Step-by-step explanation:
No but it is close. (4x +13x +10) factors into
(4x + 5)(x + 2)
So (x + 2) is a factor along with (4x + 5)
