2 years ago

Given f(t)=t to the power of 4 +t² -5, find the value of f(b) - f(-b)

2 answers:

3 0

$f(t)=t^4+t^2-5\\
\\
f(b)-f(-b)=b^4+b^2-5-[(-b)^4+(-b)^2-5]\\
\\
f(b)-f(-b)=b^4+b^2-5-b^4-b^2+5\\
\\
\boxed{f(b)-f(-b)=0}
$

DIA [1.3K]2 years ago

3 0

$f(b)-f(-b)=b^4+b^2-5-((-b)^4+(-b)^2-5)\\
f(b)-f(-b)=b^4+b^2-5-(b^4+b^2-5)\\
f(b)-f(-b)=b^4+b^2-5-b^4-b^2+5\\
f(b)-f(-b)=0
$

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