Answer:
Step-by-step explanation:
Perimeter is 70 m
so w + w + 6w + 6w = 70
w = 70/14 = 5, l = 30m.
Area = l * w = 30 * 5 = 150 sq m
Answer:
sfafafafafaq
Step-by-step explanation:
wffwafafas
Answer:
IDK
Step-by-step explanation:
There is no problem to solve
We have an equation: 2*? = 76
⇒ ?= 76/2
⇒ ?= 38
The final answer is 38~
Answer:
<h3>444m</h3>
Step-by-step explanation:
Given the height of the rocket modelled by the equation;
y=-16x^2+152x+83
The rocket reaches its maximum height when the velocity of the rocket is zero.
Since velocity is the change in displacement with respect to time;
velocity v = dy/dx
dy/dx = -32x + 152
at dy/dx = 0
-32x + 152 = 0
-32x = -152
x = -152/-32
x = 4.75s
To get maximum height reached by the ball, we will substitute x = 4.75 into the modeled function as shown;
y(4.75) = -16(4.75)^2+152(4.75)+83
y(4.75) = -361+722+83
y(4.75) = 444m
Hence the maximum height reached by the ball is 444m
