Answer:
Below.
Step-by-step explanation:
(-3, 9) - Quadrant II.
(6, -6) - Quadrant IV.
(0, -1 1/2) - x-axis 0, y-axis -1/1/2
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).
Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is = g/L
Outgoing rate =
Integrating both sides
[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram
Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get
Therefore the concentration of salt in the incoming brine is 1.73 g/L
((-9+14)/2, (-20+12)/2)
(5/2,-8/2)
(5/2,-4)
Step-by-step explanation:
D) 12 in3
How to get the volume
length x width x height
in this case it be
base x height