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2 years ago

(30/ If the surface of a lake represents a plane, what geometric

Mathematics

1 answer:

beks73 [17]2 years ago

3 0

Answer:

A point

Explanation:

The surface of a lake represents a plane because it extends in all directions at the same level. Imagine it as a quite surface, without imperfections, smooth and perfectly plane, it is a two-dimensional figure.

A fishing line that enters into the water, crossing the lake's surface, representes a line, which may be either perpendicular or leaned.

Thus the intersection of those two figures is a point.

A surface and a line that is not included in the plane and is not parallel to it will meet at a single point, which is what is represented by the situation stated.

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The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

2 years ago

A grocery store sells 6 bottles of water for $4.00 ad 15 bottles of water for $10.00. Is the cost of the water proportional to t

barxatty [35]

Yes, the cost is proportional to the number of water bottles sold. 6 water bottles/$4.00 = 1.5 and 15 water bottles/$10.00 = 1.5.

7 0

2 years ago

You start at (7,5). You move down 3 units and up 5 units Please

sergey [27]

Answer:

(4,10)

Step-by-step explanation:

7-3= 4

5=5=10

8 0

2 years ago

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likoan [24]

Answer:

1) -
2) +

3) -
4) +

Step-by-step explanation:

сумма внутренних углов треугольника не должна превышать 180 градусов

6 0

1 year ago

4. Benson sells vacuum cleaners on a commission. He earns $75 for each vacuum cleaner he sells.

Wittaler [7]

He would have to sell at least 19 vacuums.

8 0

2 years ago

Read 2 more answers