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3 years ago

Question 2

Mathematics

1 answer:

alina1380 [7]3 years ago

5 0

6/6 is not correct 88/88 jeo

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Sam bought 2 1/4 pounds of Swiss cheese and 1 1/2 pounds of cheddar at the deli. How many pounds of cheese did Sam buy altogethe

DerKrebs [107]

2 1/4 + 1 1/2

2 + 1 = 3
1/4 + 1/2 = 1/4 + 2/4 = 3/4

so ur answer is 3 3/4 lbs of cheese in total

8 0

2 years ago

4/50 converted into a percentage

Arlecino [84]

Answer:

Step-by-step explanation:

$\frac{4}{50}*100=4*2$

= 8%

3 0

2 years ago

Can u find a it please

blsea [12.9K]

Answer:

3 + 3 + 1

Step-by-step explanation:

The doubles is 3+3 which is 6 plus 1 is 7

6 0

2 years ago

The low temperature on Monday was 16°F. On Tuesday, the low was 18°F cooler. On Wednesday, the low temperature was –4 times Tues

drek231 [11]

Answer:

$-4(16-18)$ , $[16 + (-18)](-4)$

Step-by-step explanation:

Given: The low temperature on Monday was 16°F. The low temperature on Tuesday was 18°F cooler. The low temperature on Wednesday was –4 times Tuesday’s temperature.

To find: expression that can be used to describe the low temperature on Wednesday

Solution:

Temperature on Monday = 16°F

So,

Temperature on Tuesday = $(16-18)\°F$

Temperature on Wednesday = $-4(16-18)\°F$

So, expression $-4(16-18)=(16-18)(-4)$ can be used to describe the low temperature on Wednesday.

Also,

$(16-18)(-4)=[16 + (-18)](-4)\,\,\left \{\because (a-b)=\left [ a+(-b) \right ] \right \}$

So, expression $[16 + (-18)](-4)$ also represent temperature on Wednesday.

3 0

2 years ago

Read 2 more answers

What is the solution set of x2 + 5x + 1 = 0?

DerKrebs [107]

Answer:

$\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}$

Step-by-step explanation:

$x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}$

$\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}$

3 0

2 years ago