Write an equation of a line in slope intercept form (y = mx + b) with slope 1/3 going through the point (-6, 2)

1 answer:

4 0

y = mx + b
slope 1/3 = m
going through the point (-6, 2)
so
2 = 1/3(-6) + b
2 = -2 + b
b = 4

equation
y = mx + b
y =1/3x + 4

answer
y =1/3x + 4

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find a parametric representation of the solution set of the linear equation. (enter your answer as a comma-separated list of equ

Ostrovityanka [42]

To represent the solution set of a linear equation parametrically, we introduce other parameters like s and t for the free variables.

Every linear equation has n - 1 free variables where n is the number of variables.

For x + y + z = 2, we have 3 variables and 3 - 1 = 2 free variables.

First, let y and z be the free variables, we first solve the linear equation for x to get:

x = 2 - y - z

Therefore , the parametric representation of the solution set is given by :

x = 2 - s -t

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The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.

erma4kov [3.2K]

Answer:

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

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Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

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To Find:

Curved surface area
Volume

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Solution:

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Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

Substituting the required values: 

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$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

Substituting the required values, 

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$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$