Answer:
3.416 m/s
Explanation:
Given that:
mass of cannonball = 72.0 kg
mass of performer = 65.0 kg
The horizontal component of the ball initially = 6.50 m/s
the final velocity of the combined system v = ????
By applying the linear momentum of conservation:
v = 3.416 m/s
The mechanical efficiency = actual work / ideal work
So ζ = 1540 / 1600 * 100% = 96.25%
Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:
where F is the force applied, and
is the stretch of the spring with respect to its equilibrium position. Using the data, we find
Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
Answer:
x = 0.0734 m = 7.34 cm
Explanation:
First we shall calculate the area of the piston:
Now, we will calculate the force on the piston due to atmospheric pressure:
Now, for the compression of the spring we will use Hooke's Law as follows:
where,
k = spring constant = 3400 N/m
x = compression = ?
Therefore,
<u>x = 0.0734 m = 7.34 cm</u>