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2 years ago

How do u solve 3= t + 11.5 - t ?

Mathematics

1 answer:

shepuryov [24]2 years ago

7 0

11.5

itssssssssssssssssssssssssssssssssssssssssssssssss

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The area of the vegetable garden is 0.4 of the community area of 4.5 x 6.2 . What is the area of the vegetable garden?

Gala2k [10]

Answer:

11.16 units²

Step-by-step explanation:

Area of community area=4.5×6.2= 27.9 units²

Area of vegetable garden=27.9×0.4=11.16 units²

5 0

2 years ago

If minor arc AB measures 9 inches, what is the length of the radius of circle C? If necessary, round your answer to the nearest

Art [367]

Complete Question

If minor arc AB measures 9 inches, what is the length of the radius of circle C? Where the radians is 0.75 radians

If necessary, round your answer to the nearest inch. 6 inches 12 inches 18 inches 24 inches

Answer:

12 inches

Step-by-step explanation:

The formula for Arc length =

Arc length = r θ

θ = 0.75

Arc length = 9 inches

Hence:

r = 9/ θ

r = 9/0.75

r = 12 inches

3 0

2 years ago

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PLEASE I NEED HELP RN

Alona [7]

Answer:

Number A is correct I think, coz if uu take the feet convert them into decimals u'll get accurate answers

8 0

2 years ago

A random sample of math majors taking an introductory statistics course were surveyed after completing the final exam. They were

quester [9]

Answer:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

Step-by-step explanation:

For this case we have the following distribution given:

X 1 2 7

P(X) 1/5 2/5 2/5

We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8$

Now we can find the second moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4$

The variance would be given by:

$Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96$

And the deviation would be:

$Sd(X) =\sqrt{6.96}= 2.638$

7 0

2 years ago

Simplify the power of i^15

TiliK225 [7]

Answer:

this cant be simplified unless you have an integer in place of "i"

4 0

2 years ago

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