Question

How long can a flashlight run for if it draws 0.11 amps and its battery contains 10 coulombs of change?

Answer 1

Answer:

Battery will run for t = 90 s

Explanation:

As we know that rate of flow of charge is known as electric current

So we will have

$i = \frac{Q}{t}$

$i = 0.11 A$

$Q = 10 C$

now we have

$t = \frac{Q}{i}$

$t = \frac{10}{0.11}$

$t = 90 s$