When using ANOVA procedures, the research hypothesis is: there is no significance difference within the mean values of the groups.
<h3>What is a Research Hypothesis in ANOVA Procedure?</h3>
ANOVA procedure compares the mean values of different groups that are administered with treatments. The research hypothesis, such as the null hypothesis would be stated as: no significance difference in the mean values within the groups.
Thus, we can conclude that the research hypothesis when using the ANOVA procedures can be stated as a null hypothesis, which states that: there is no significance difference within the mean values of the groups.
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Answer:
108,000,934
1.08934×10^8
Step-by-step explanation:
(302)^3
(a+b)^3
(a+b)^3==a^3+3a^2b+3ab^2+b^3
(300+2)
(300)^3+3(300^2+2)+3(300+2^2)+2^3
27,000,000+81,000,002+8+924
108,000,002+8+924
108,000,934 or 1.08934×10^8
The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
The length of a new rectangle playing field is 6 yards longer than quadruple the width.
Let's suppose the length is l and width is w of a rectangle:
From the problem:
l = 6 + 4w
Perimeter P = 2(l + w)
532 = 2(l + w)
Plug l = 6+4w in the above equation:
532 = 2(6 + 4w + w)
266 = 6 + 5w
260 = 5w
w = 52 yards
l = 6 +4(52) = 214 yards
Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
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Answer:
553 km
Step-by-step explanation:
1:55.3 to 10:553
Answer:
c ?
Step-by-step explanation: