Answer:
It is impossible to find two points that are both 1 inch and 1.5 inches from the point A simultaneously as shown in the following proof
From segment addition postulate given a point C that is between the points of a segment AB, we have;
AC + CB = AB
Therefore, where AC = 1 inch and CB = 1.5 inches, we have;
AC + CB = 1 inch + 1.5 inches = 2.5 inches ≠ AB = 3 inches
However it is possible to find two points in which one of the points is 1 inch from the point A while the other point is 1.5 inches from the point B
Step-by-step explanation:
Simplify the following:
(18 x - 108)/(6 x - 54)
Factor 6 out of 6 x - 54:
(18 x - 108)/(6 (x - 9))
Factor 18 out of 18 x - 108:
(18 (x - 6))/(6 (x - 9))
18/6 = (6×3)/6 = 3:
Answer: (3 (x - 6))/(x - 9)
V(sphere)=4/3 * pi * r^3
heights in a sphere = 2r
v(cone)= 1/3 pi r^2 h
With same height, it would be 1/3 pi r^2 2r = 2/3 pi r^3
4/3 / 2/3 = 2
So the cone is half of the volume of the sphere
Answer:
If Frank is planting b seeds in one and 5b + 10 in the other, the expression showing the total is b + (5b + 10), or 6b + 10 seeds.
brainliest?
The answer is 23 I’m pretty sure that’s correct
