1.
12 liters of 26% acid solution contain
liters of acid.
x liters of 40% acid solution contain
liters of acid.
The third solution is made from the two mixed solution so its volume is
, and the volume of acid in it is
. Its concentration is 33% or 0.33.
The concentration of a solution is the volume of the solution divide by the volume of acid in it.
The answer is B.
2.
12 liters of 16% acid solution contain
liters of acid.
x liters of 40% acid solution contain
liters of acid.
The volume of the third solution is
, and the volume of acid in it is
. Its concentration is 32% or 0.32.
The answer is B.
3.
16 liters of 18% acidsolution contain
liters of acid.
x liters of 27% acid solution contain
liters of acid.
The volume of the third solution is
, and the volume of acid in it is
. Its concentration is 21% or 0.21.
The answer is A.
Answer:
x + 5
Step-by-step explanation:
3x + 5 -4x - 10
Combine like terms.
-x -5
Divide by -1
x + 5
I hope that this helps! :)
The answer would be .... d hoped i helped
Find the area of the CD. (I used P for pi, too lazy @
[email protected])
A=Pr² - Pr²
radius of the small hole in the middle, 0.75cm
radius of the CD, 6cm
A=3.14*6²-3.14*0.75²
A=111.27375cm²
The Approximate area of the CD is 111.27cm²
Answer:
THE ANSWER IS 30
Step-by-step explanation:
We can solve this problem by multiplication expressions. See below.
1/6 ÷5 30