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2 years ago

PLEASE HELP! I will give brainliest

Chemistry

1 answer:

horsena [70]2 years ago

6 0

Answer:

3.07g of NaCl are present in the solution

Explanation:

A 1.05 M NaCl solution means you have 1.05 moles of NaCl per liter of solution. In 50.0mL = 0.0500L you will have:

0.0500L * (1.05mol / L) = 0.0525 moles of NaCl.

To convert these moles to grams you must use molar mass of the compound (Molar mass NaCl: 58.44g/mol). In 0.0525 moles of NaCl you will have:

0.0525mol * (58.44g / mol) =

<h3>3.07g of NaCl are present in the solution</h3>

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1 year ago

What mass of HgO is required to produce 0.692 mol of O2? 2HgO(s) -> 2Hg(l) + O2(g)

Vika [28.1K]

The answer for the following problem is mentioned below.

Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule

Explanation:

Given:

no of moles of the oxygen gas = 0.692

Also given:

2 HgO → 2 Hg + $O_{2}$

where,

HgO represents mercuric oxide

Hg represents mercury

$O_{2}$ represents oxygen

To calculate:

Molar mass of HgO:

Molar mass of HgO = 216 grams

molar mass of mercury (Hg) = 200 grams

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HgO = 200 +16 = 216 grams

We know;

2×216 grams of HgO → 1 mole of oxygen molecule

? → 0.692 moles of oxygen molecule

= $\frac{2*216*0.692}{1}$

= 298.944 grams of HgO

Therefore 298.44 grams of mercuric oxide is needed to produce 0.692 moles of oxygen molecule

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