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2 years ago

5

Answer pleaseeeee?:)

1 answer:

gtnhenbr [62]2 years ago

4 0

If I were to tell a kid how to use the formula (the SA of a pyramid it looks like):

First, find the area of the base of the figure, using length times width.

Next, find the perimeter of the base by adding up the length of each side of the base.

Multiply the perimeter of the base by the slant height of the figure, which is the line on the side of the figure that is diagonal.

Divide the answer you got from multiplying the perimeter of the base times the slant height of the base by 2.

Now add up the area of the base of the figure with the answer you just got by dividing the perimeter of the base times the slant height by 2.

That is how you use the formula: SA = B + 1/2(P · l)

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2 years ago

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NISA [10]

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Step-by-step explanation:

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lets call to this integral, the integral Io.

for a general form of I you have In:

$I_n=\int_0^{\infty}x^ne^{-ax^2}dx$

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by using this last expression in an iterative way you obtain the following:

$\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}}$ (2)

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$\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}$

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2 years ago

Read 2 more answers

How to i solve for x in this situation? thank yous.

Lena [83]

i did not understand the question can u explain again i can help u

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Step-by-step explanation:

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