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2 years ago

For the functions f(x)=−7x^2−x and g(x)=9x^2−4x, find (f−g)(x) and (f−g)(1)

Mathematics

1 answer:

musickatia [10]2 years ago

5 0

Answer:

See below.

Step-by-step explanation:

$f(x)=-7x^2-x\\g(x)=9x^2-4x\\(f-g)(x)=f(x)-g(x)\\(f-g)(x)=(-7x^2-x)-(9x^2-4x)\\(f-g)(x)=-7x^2-x-9x^2+4x\\(f-g)(x)=-16x^2+3x\\\\(f-g)(1)=-16(1)^2+3(1)\\(f-g)(1)=-16+3=-13$

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What sum will amount to rupees 4000 in 3 years at 6% p.a. compound interest

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Answer:

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⇢ Principle = Rs.4000
⇢ Rate = 6%
⇢ Time = 3 year

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$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{purple}{To Find:}}}}}}}\end{gathered}$

⇢ Amount

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${\dag{\underline{\boxed{\sf{Amount ={P{\bigg(1 + \dfrac{R}{100}{\bigg)}^{T}}}}}}}}$

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Substituting the values

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg(1 + \dfrac{6}{100}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg(1 \times 100 + \dfrac{6}{100}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{100 + 6}{100}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{106}{100}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg({\cancel{\dfrac{106}{100}}{\bigg)}}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{53}{50}{\bigg)}^{3}}}}}}$

$\quad {:\implies{\sf{Amount = \bf{4000{\bigg( \dfrac{53}{50} \times \dfrac{53}{50} \times \dfrac{53}{50}{\bigg)}}}}}}$

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$\quad {:\implies{\sf{Amount = \bf{4000 \times \dfrac{148877}{125000}}}}}$

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$\quad {:\implies{\sf{Amount = \bf{\dfrac{595508}{125}}}}}$

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m_a_m_a [10]

First blank: Substitution or transitive property of equality

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umka2103 [35]

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Step-by-step explanation:

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3 years ago

A triangle has side lengths of (1.3k+3.5m)(1.3k+3.5m) centimeters, (4.1k-1.6n)(4.1k−1.6n) centimeters, and (9.7n+4.4m)(9.7n+4.4m

Scorpion4ik [409]

Answer:

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Step-by-step explanation:

Given the side length of a triangle;

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Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters

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2 years ago