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2 years ago

What is the basic ratio for 120:150

Mathematics

2 answers:

SCORPION-xisa [38]2 years ago

4 0

No, it is 4:5.... if you’re simplifying it... if you divide 4 by 30 it is 120 and 5 Times 30 is 150 so it’s 120:150 4:5

OleMash [197]2 years ago

3 0

I am not 100% shod but it should be 12:15. As you are dividing both sides by the same number. The easiest way is to first cancel out the 0s.

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A road rises 50 feet over a horizontal distance of 600 feet. What is the slope of the road?

Hatshy [7]

Answer:

1/12 (or 0.833)

Step-by-step explanation:

Recall that the definition of "slope" is the change in vertical distance divided by the change in the horizontal distance. (aka. rise ÷ run)

it is given that rise = 50 feet and the horizontal distance (i.,e "run") = 600feet

hence slope = rise / run = 50 / 600 = 1/12 (or 0.833)

6 0

2 years ago

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Help!!! (Tell me if you can’t see it clearly)

meriva

I believe it’s option c!

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2 years ago

Solve the system by substitution.<br> y = -7x. y = -5x + 10

ohaa [14]

Answer: (-5,35)

Step-by-step explanation:

-7x=-5x+10

Get x on one side by adding 5x

-2x=10

Simplify by dividing by -2

X=-5

Substitute into y=-7x

Y=-7(-5)

Simplify

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2 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

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Setler [38]

Answer:

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x − 6

Step-by-step explanation:

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