Answer:
The <u>shape in V</u> of the vomerine teeth is useful to <u>hook the prey and hold i</u>t until the frog can swallow it.
Explanation:
In frogs, we can distinguish maxillary teeth, premaxillary teeth, and Vomerine teeth.
Vomerine teeth are projections of the vomer bone, located in the anterior part of the paladar and between the internal nares.
Vomerine teeth are specialized structures that help frogs catch and hold their prey. They are not involved in chewing or killing (frogs swallow the entire prey alive), just holding the creature before swallowing it.
These projections are covered by soft tissue. When the frog catches the prey, presses the tongue against the roof of your mouth. The vomerine teeth hook the prey and prevent it from slipping or wandering away.
The<u> shape in V</u> of the vomerine teeth is useful <u>to hook the prey and hold it </u>until the frog can swallow it.
Hello!
False! They vary from crystal to crystal. Nothing is ever honestly the same size of one another, especially not crystals. They're all different, like snowflakes.
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Answer:
Primary active transport
Explanation:
Primary active transport is the transport in which molecules are moved against their gradient, with direct use of ATP as an energy source. Na/K pump is an example of primary active transport: Na ions are transported out of cell, K ions are moved into the cell. This pumps maintain concentrations of those ions and also creates voltage across the cell membrane, which can be used for the secondary active transport of other molecules (e.g. glucose).
Answer:
0.095
Explanation:
Phenylkentonuria is a disease caused by a recessive allele.
The frequency of the recessive allele + the frequency of the dominant allele equals 1.
The frequency of the recessive allele is q = 0.05
The frequency of the dominant allele then is p = 1 - q = 0.95
If people mate randomly, the frequency of the homozygous dominant genotype will be p², the frequency of the heterozygous genotype will be 2pq and the frequency of the homozygous recessive genotype will be q² .
2pq=2× 0.05 × 0.95
2pq=0.095
The heterozygote frequency in the population is 0.095
