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2 years ago

Given the following reaction: NH4SH (s) <--> NH3 (g) + H2S (g) If we start

Chemistry

1 answer:

almond37 [142]2 years ago

4 0

Answer:

D. 0.3 M

Explanation:

NH4SH (s) <--> NH3 (g) + H2S (g)

Initial concentration 0.085mol/0.25L 0 0

Change in concentration -0.2M +0.2 M +0.2M

Equilibrium 0.035mol/0.25 L=0.14M 0.2M 0.2M

concentration

Change in concentration (NH4SH) = (0.085-0.035)mol/0.25L =0.2M

K = [NH3]*[H2S]/[NH4SH] = 0.2M*0.2M/0.14M ≈ 0.29 M ≈ 0.3M

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