Answer:
225.78 grams
Step-by-step explanation:
To solve this question, we would be using the formula
P(t) = Po × 2^t/n
Where P(t) = Remaining amount after r hours
Po = Initial amount
t = Time
In the question,
Where P(t) = Remaining amount after r hours = unknown
Po = Initial amount = 537
t = Time = 10 days
P(t) = 537 × 2^(10/)
P(t) = 225.78 grams
Therefore, the amount of iodine-131 left after 10 days = 225.78 grams
The answer is 3n^2+1
9n^2 - 6n^2 = 3n^2
3n-3n=0
4-3=1
Answer:
y=2x+5
Step-by-step explanation:
0,5
0,7
7-5 is 2
2/0 is 2
to check answer:
(2*0)+5
0+5
=5
Answer:
meema, papa, and then auntie jo
Step-by-step explanation:
you need to find the slope of each of them and then determine which one is the fastest and which one is the slowest.
meema: 48-24/4-2 = 4/2 = 2
papa: 40-24/5-3 = 16/2 = 8
auntie jo: 45-18/5-2 = 27/3 = 9
im in algebra two so you can trust my answer. happy holidays and stay safe!
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
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