Answer:
The amount of acid in third container is =42%
Step-by-step explanation:
Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .
Let, the volume of first container is = x
Then , the volume of second container = (x+ x of 50%)
= x + 0.5 x
= 1.5 x
Therefore the amount of acid in first container = 0.3 x
The amount of acid in second container = 0.75x
Total amount of acid= 0.3x + 0.75x = 1.05 x
Total amount of solution = x+1.5x = 2.5x
The amount of acid in third container is = %
= 42%
<u>Part</u><u> </u><u>1</u> 6(1.20)+4(1.05)=$11.40
<u>Part</u><u> </u><u>2</u> 1.20x+1.05y
Answer: The first one. 2 to the 20th power over 3 to the 8th power
Step-by-step explanation:
Answer:
4/10
Step-by-step explanation:
2/72 = 36
2/36 = 18
2/18 = 9
3/9 = 3
3/3 = 1
so now as you can see we have 3 number which is divided by 2 and 2 numbers which is divided by 3. so it becomes, 3*2√2 = 6√2 is final answer.