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2 years ago

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How are Piaget and Erikson's theories different?

2 answers:

SOVA2 [1]2 years ago

8 0

D) all of the above is the answer

jok3333 [9.3K]2 years ago

8 0

Answer:

D) all of the above

Explanation:

Piaget and Erikson's theories are different in m,any ways which are described below:

According to Piaget theory of development a person can not essentially go through all phases of his theory of development but according to Erikson, a person can go through all stages of development up to his old age. Here they have differ aspects of Human development.
Piaget theory describes the four stages of child in which transition is from one state to another is linked by a sequence whereas Erikson's theory dealt with eight stages of development throughout the life of a person.
According to the Piaget stages are going through the sequence like, sensorimotor stage, concrete stage, period of preoperational and formal operation stage whereas according to Erikson, people goes through stages as, autonomy vs shame and doubt, trust vs. mistrust, initiative vs. guilt and so on.

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1. Earth releases about 44-46 Tw of heat, in fact heat can be converted into

Aleksandr [31]

Answer:

even if it all could be used, it wouldn't be enough

Explanation:

The land area of the US is about 5.45% of the world's area, so the amount of released heat over the area of the US is on the order of 2.4 Tw. Current technology for converting geothermal energy to electricity is about 12% efficient, so the available energy might amount to 0.29 Tw if it could all be captured.

Energy consumption in the US in 2019 was on the order of 0.46 Tw. This suggests that even if <em>all</em> of the thermal energy radiated by the Earth from the US could be turned to useful forms of energy, it would meet only about 60% of the US need for energy.

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2 years ago

A 570 kg elevator accelerates downwards at 1.5 m/s2 for the first 13 m of its motion.

jeka94

Mass of the elevator (m) = 570 Kg
Acceleration = 1.5 m/s^2
Distance (s) = 13 m
Let the force be F.
We know, F = ma,
Therefore, F = (570 × 1.5) N = 855 N
Angle between distance and force (θ) = 0°
We know, work done = F s Cos θ
Therefore, work done by the cable during this part
= (855 × 13 × Cos 0°) J
= (855 × 13 × 1) J
= 11115 J

<u>Answer</u><u>:</u>

<u>1</u><u>1</u><u>1</u><u>1</u><u>5</u><u> </u><u>J</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0

2 years ago

A push or pull exerted on an object

r-ruslan [8.4K]

Force-a push or pull exerted on an object.

4 0

2 years ago

Analogies exist between rotational and translational physical quantities. Identify the rotational term analogous to each of the

damaskus [11]

Explanation:

Acceleration. Angular acceleration: Is the rate of change of the angular velocity of a body with respect to time.

Force. Torque: Is also called rotational force, since an applied torque will change the rotational motion of a body.

Mass. Moment of inertia: It is the resistance that opposes a body to rotates.

Work. Work: In a rotational motion, the work is done by the torque.

Translational kinetic energy. Rotational kinetic energy: is the kinetic energy due to the rotational motion of a body.

Linear momentum. Angular momentum: Represents the quantity of rotational motion of a body.

Impulse. Angular impulse: Is the change in angular momentum of a body.

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2 years ago

The de broglie wavelength of an electron with a velocity of 6.00 × 106 m/s is ________ m. The mass of the electron is 9.11 × 10-

WINSTONCH [101]

Answer: $1.212(10)^{-10} m$

Explanation:

The de Broglie wavelength $\lambda$ is given by the following formula:

$\lambda=\frac{h}{p}$ (1)

Where:

$h=6.626(10)^{-34}\frac{m^{2}kg}{s}$ is the Planck constant

$p$ is the momentum of the atom, which is given by:

$p=m_{e}v$ (2)

Where:

$m_{e}=9.11(10)^{-28}g=9.11(10)^{-31}kg$ is the mass of the electron

$v=6(10)^{6}m/s$ is the velocity of the electron

This means equation (2) can be written as:

$p=(9.11(10)^{-31}kg)(6(10)^{6}m/s)$ (3)

Substituting (3) in (1):

$\lambda=\frac{6.626(10)^{-34}\frac{m^{2}kg}{s}}{(9.11(10)^{-31}kg)(6(10)^{6}m/s)}$ (4)

Now, we only have to find $\lambda$ :

$\lambda=1.2122(10)^{-10} m$ >>> This is the de Broglie wavelength of the electron

8 0

2 years ago